html数据表单两个按钮提交,如何在单个HTML表单中处理两个不同的提交按钮？

如果我有一个表格,如下面的脚本:

session_start();

$con=mysqli_connect(“localhost”,”root”,””,”QSTNS”);

if (mysqli_connect_errno()) {

echo “Failed to connect to MySQL: ” . mysqli_connect_error();

}

$dsply=$_SESSION[‘q_indx’][$_SESSION[‘cindx’]] ;

//echo $dsply ;

$qstn = mysqli_query($con,”SELECT * FROM qstns where qid = ‘”. $dsply .”‘”);

$qstn = $qstn->fetch_array(MYSQLI_ASSOC);

//echo $qstn[‘qname’] . “
“;

//echo $qstn[‘opta’] .”
“;

//echo $qstn[‘optb’].”
“;

//echo $qstn[‘optc’].”
“;

//echo $qstn[‘optd’].”
“;

mysqli_close($con);

?>

<?php echo $qstn[‘qname’] .”
“; ?>

我在一个表单中有两个按钮,我想分别处理每个按钮,为此我使用了isset()但它没有用.下一页的代码是:

session_start() ;

$con=mysqli_connect(“localhost”,”root”,””,”QSTNS”);

if (mysqli_connect_errno()) {

echo “Failed to connect to MySQL: ” . mysqli_connect_error();

}

if (isset($_POST[‘previous’])) {

if($_SESSION[‘cindx’]>0)

$_SESSION[‘cindx’]-=1;

}

if(isset($_POST[‘next’]))

{

$res=mysqli_query($con, ‘SELECT COUNT(*) FROM qstns’);

$row = mysqli_fetch_array($res);

//echo $row[0];

if($_SESSION[‘cindx’]

$_SESSION[‘cindx’]+=1;

}

//echo ‘here’;

header(‘Location: quiz_start.php’);

mysqli_close($con);

?>

有人可以帮忙吗？