乱暴力就可以了….
1 second
256 megabytes
standard input
standard output
One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were x details in the factory storage, then by the end of the day the factory has to produce 
(remainder after dividing xby m) more details. Unfortunately, no customer has ever bought any mythical detail, so all the details produced stay on the factory.
The board of directors are worried that the production by the given plan may eventually stop (that means that there will be а moment when the current number of details on the factory is divisible by m).
Given the number of details a on the first day and number m check if the production stops at some moment.
The first line contains two integers a and m (1 ≤ a, m ≤ 105).
Print “Yes” (without quotes) if the production will eventually stop, otherwise print “No“.
1 5
No
3 6
Yes
/**
* Created by ckboss on 14-11-7.
*/
import java.util.*;
public class CF485A
{
public static void main(String[] args)
{
HashSet<Integer> hi = new HashSet<Integer>();
Scanner in = new Scanner(System.in);
int a,m;
a=in.nextInt(); m=in.nextInt();
boolean flag=false;
for(int i=0;i<=100000;i++)
{
a=(a+a%m)%m;
if(hi.contains(a)==true)
break;
hi.add(a);
if(a%m==0)
{
flag=true; break;
}
}
if(flag==true)
System.out.println("Yes");
else
System.out.println("No");
}
}